by dscpcb » Fri Sep 11, 2015 12:38 pm
The Q, or quiescent point, is the DC level, or where the circuit produces no noise.
The first thing to do would be to Thevenize the left side of the circuit; Vth = 24K/(24K+96K) * Vcc, Rth = 96K in parallel with 24K.
Once you solve those, you will have a circuit with an a voltage source on the left (Vth) and a resistor, Rth, between Vth and Vbe.
To solve for the current i(b), use i(b) = (Vth - Vbe)/Rth
Once you have i(b), you should be able to find i(c) and Vce, and then verify that the circuit is in active mode.